22x^2+8x=81

Solution for 22x^2+8x=81 equation:

22x^2+8x=81

We move all terms to the left:

22x^2+8x-(81)=0

a = 22; b = 8; c = -81;
Δ = b2-4ac
Δ = 82-4·22·(-81)
Δ = 7192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7192}=\sqrt{4*1798}=\sqrt{4}*\sqrt{1798}=2\sqrt{1798}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{1798}}{2*22}=\frac{-8-2\sqrt{1798}}{44}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{1798}}{2*22}=\frac{-8+2\sqrt{1798}}{44}
$